h(x) = the integral from 0 to x^2 of the function squareroot(1+r^3) dr
Is the answer = [squareroot(1+x^3)]* (2x)??
I tried using the fundamental theorem of calculus in conjunction with the chain rule but did I use it correctly?
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h(x) = the integral from 0 to x^2 of the function squareroot(1+r^3) dr
Is the answer = [squareroot(1+x^3)]* (2x)??
I tried using the fundamental theorem of calculus in conjunction with the chain rule but did I use it correctly?
This integral is not easily evaluated by elementary means. That's what leads me to
believe you're leaning toward the SECOND fundamental theorem of calculus.
This gives
You're close. It's
Oh wow.. I multiplied wrong haha. Thank you very much! It was very helpful!
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