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  • Aug 2, 2005, 06:19 AM
    shupper
    Percentages
    I can't figure this out

    A chemist mixed some 15% solution with some 6% solution to make 300 ml of a 9% soulution. How many ML of the 15% were used?


    Please help me
  • Aug 2, 2005, 06:56 AM
    CroCivic91
    You can set a formula like this:

    X * 15% + Y * 6% = 300 * 9% and X + Y = 300

    X says how much of 15% solution is used, and Y says how much of 6% solution was used. You want to know how much is X.

    So you have a system of equations. You do like this:

    Y = 300 - X that's from second formula
    put that into first and you get
    X*15% + (300 - X)*6% = 300*9%
    x*15% - x*6% = 300*9% - 300*6%
    multiply whole formula by 100 and get
    15x - 6x = 300*9 - 300*6
    9x = 300*3 = 900
    x = 100

    So, 100ml of 15% solution was used.

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