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-   -   Standard enthalpy of combustion (https://www.askmehelpdesk.com/showthread.php?t=103747)

  • Jun 23, 2007, 02:29 PM
    shrek
    Standard enthalpy of combustion
    Here's the problem

    The heat of combustion for 1 mole of carbon to carbon dioxide is -410 kj. How many kj's of heat would be liberated from the complete combustion of 60.0 g of carbon?
  • Jun 23, 2007, 04:06 PM
    tickle
    Are you talking about nuclear energy ?
  • Jun 23, 2007, 04:13 PM
    Capuchin
    No tickle, this is standard molecular chemistry.

    Shrek, do you know how to calculate the mass of a single mole?
  • Jun 23, 2007, 08:14 PM
    crazygirl13455
    If heat of comubustion and heat of fusion are the same thing then it should be 24600kJ
  • Jun 24, 2007, 07:50 PM
    crazygirl13455
    OK. Work: if it is the heat of fusion that means that the q (or heat)= mHf (mass x heat of fusion) so -410x60 = -24600 [i forgot the negative in my first answer] the negative I'm pretty sure means it's exothermic
  • Jun 24, 2007, 11:30 PM
    Capuchin
    No, you need to convert the mass into moles.

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