I have no idea how to solve this!
It's about Verifying trigonometric identities.
Here's the problem:
1 divided by 1+tanx = cotx divided by 1+cotx
I have no idea how to solve this!
It's about Verifying trigonometric identities.
Here's the problem:
1 divided by 1+tanx = cotx divided by 1+cotx
Wouldn't it be easier to write:
1/(1+tan(x))=cot(x)/(1+cot(x))
Or, in LaTeX:
To see the code I used to make it display that way, click on 'quote' at the lower right corner of this post.
Just cross multiply:
Now, can you see it? What does
equal?
THank you !
So for another one, I have
4tanxcos²x-2tanx/1-tan²x=2tanx/1-tan²x.
So far, I have simplified it to 2tanxcos²x/1-tan²x.
Could I set up a proportion setting my identities equal to each other?
Are you allowed to cross multiply in proving identities :confused:
My method would be to divide both sides by tan, or cot, depending on where you are starting from.
This is using the fact that
~~~~~~~~~~~~~~~~
I don't think this is a true identity, because:
Multiply both sides by 1 - tan^2x gives a new identity:
Adding 2 tan x to give this new identity:
Factor 4tan x on the left:
Simplifies to
And as required for the identity to be true.
Either that, or you did a typing mistake, the identity should be instead:
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