I am having a hard time transposing this equation.
P = 2Pi(F1 - F2)(r) n/60 find for n.
So far I have P/2Pi=(F1-F2)(r)n/60

My next step that I can think of is to multiply both sides by 60 so it woul look like
(60)P/2Pi=(F1-F2)(r)(n).

I don't just keep stacking the division up on the left hand side do I?

You're doing it right. You don't "stack up" the divisions, they just go on the bottom. Emember that dividing by r is the same as multiplying by 1/r, if that makes it easier.

Hint: You can do it in one step by multiplying bothe sides by 60/(2Pi(F1 - F2)(r))

Quote:

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Originally Posted by Capuchin

You're doing it right. You don't "stack up" the divisions, they just go on the bottom. emember that dividing by r is the same as multiplying by 1/r, if that makes it easier.

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So my answer would be n = P(60/2π(F1-F2)(r))

Yup :)

It's nice and easy when everything is division or multiplication.

It gets a bit trickier when the thing you need to transpose for is being added to or taken away from.

In transposing whatever you do to one side you do to the other side. P= [2Pi(F1-F2)r] N / 60
1] Multiply both sides by 60 / 60 P = [2Pi(F1-F2)r] N 60 /60 After cancelling/ 60 P = [2Pi(F1-F2)r]N
2] Divide both sides by [2Pi(F1-F2)r] 60 P /[2Pi(F1-F2)r] = N
3] Bring over to to the left hand side of the equation if you like.