Please help in this problem.. Here's the problem:
A body rises vertically from earth according to the law S= 64t - 16t^2. In here, I need to show or prove that it has lost one-half its velocity in the first 48ft. Of rise.
Another thing.. can you please check if my answer in this problem is correct.. :)
A particle is moving along a horizontal line according to the formula S= 1/3 t^3 - 1/2 t^2 - 2t + 2 whose S feet is the distance of the particle from the origin at time t(secs).
a.) what is the instantaneous velocity of the particle at t=2?
my answer: v=0
b.) when is the particle is at rest? When v=0, t>2 and t>-1
c.) when is the particle moving to the right? When v>0.
Hope you can help me. Thanks a lot.