five decreased by eleven times a number is greater than 71. Evaluate this problem situation for values of the number.

Gosh, it's been a while since I've done this stuff but it seems this would be what you are looking for:

5-11x>71

OH yeah, so to finish it would be like this:

5-11x>71
-5... -5

-11x>71-5

-11x>66
---- ----
-11... -11

x>-6

I didn't check that answer against the original formula but it seems right from here.

(and sorry for the... 's, I had to do that to make it line up in the right spot)

the sum of three consecutive integers is 48. What is the set of the three consecutive integers that fit the situation?