kinetic and potential energy
A stone weighing 0.2 kilograms is thrown vertically upwards with a velocity of 19.6 meters per second. Neglecting the friction of the air, calculate the kinetic and potential energy it possesses at the end of 1 second and 2 seconds respectively.
I have this so far: PE=mgh.. therefore it should be 0 because there is no height to account for? Is that correct?
Also Kinetic energy is 1/2mv^2 which would equal 38.416. However, I don't understand how to account for the 1 and 2 seconds. Any help you could give me?