I really don't know, can someone help me...
I really don't know, can someone help me...
simple algebra:
This will give you the lowest value of x. You need to remember that there are in fact an infinite number of values for x, as the graph at the bopttom of the post shows. Each of my lines shows the positions of solutions to sin(2x) = 1/2 between 0 and 10. Working them out should be fairly trivial.
Let me know if you need more help!
Graphic side is OK, but nul points aren't asigned so I can only assume what are they
I wasn't dividing by sin, i was using the inverse sin operator on both sides, where . This is perfectly acceptable, and all scientific calculators have this function.
Also, the graph wasn't for you to read off the answer, it was to show you that there are an infinite number of values of 2x. Your answer gives only one of them (and i point out that your solution is the same as mine!).
[ sin(x) / sin ] =x
sorry, not used to write sin all alone...
you used the arc function... sin^(-1) = arc
I used the same function in my 3rd step...
both our solutions are correct...
and I would like to apologise to you for calling you insane, sorry ,)...
generally, ^(-1) of a function implies the inverse of the function. For example if f(x) = 2(x^2) then f^-1(x) = (1/2x)^0.5. not simply 1/f(x)
You need to recognise the other solutions, x=pi/12 isn't the only answer. You don't have a complete solution yet.
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