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-   -   How do you solve/graph this. ABSOLUTE VALUE? (https://www.askmehelpdesk.com/showthread.php?t=213007)

  • May 5, 2008, 10:30 PM
    dreams2big2keep
    How do you solve/graph this. ABSOLUTE VALUE?
    Absolute value??

    y= -lx+2l+3

    how do I graph it?? Please help?
  • May 6, 2008, 07:38 AM
    iamthetman
    Plot the points on a graph.
    x=3 -> y=-2
    x=2 -> y=-1
    x=1 -> y=0
    x=0 -> y=1
    x=-1 -> y=2
    x=-2 -> y=3
    x=-3 -> y=4

    You'll notice that you have a straight line!
  • May 6, 2008, 07:44 AM
    retsoksirhc
    Quote:

    Originally Posted by iamthetman
    Plot the points on a graph.
    x=3 -> y=-2
    x=2 -> y=-1
    x=1 -> y=0
    x=0 -> y=1
    x=-1 -> y=2
    x=-2 -> y=3
    x=-3 -> y=4

    You'll notice that you have a straight line!

    I disagree...

    Following the equation y= -lx+2l+3

    For x=-3, y= -|-3+2| +3
    y=-|-1|+3
    y=-1+3
    y=2

    Absolute values make a V shaped graph.
  • May 6, 2008, 08:02 AM
    iamthetman
    So essentially what you have is this:
    x=3 -> y=-2
    x=2 -> y=-1
    x=1 -> y=0
    x=0 -> y=1
    x=-1 -> y=2
    x=-2 -> y=3
    but then when you get to x=-3 you notice a change:
    x=-3 -> y=2
    x=-4 -> y=1
    x=-5 -> y=0
  • May 6, 2008, 12:29 PM
    galactus
    1 Attachment(s)
    Here's the graph:
  • May 6, 2008, 01:08 PM
    retsoksirhc
    Nice, galactus. What did you use to make that? It's pretty spiffy.
  • May 6, 2008, 02:42 PM
    galactus
    I done that with a FREE graphing download you can get at Graph

    Download it. It's absolutely free. It graphs standard, parametric, and polar. As well as finding area, finding tangent lines, etc.
  • Feb 1, 2010, 04:31 AM
    noor 123
    x -1 0 1
    Y=3x+5

    plot the points and draw a straight line through the ponts.
    from the graph,find:-
    the values of y when x=2,0.6 and 1.5
    the values of x when y=1,0.8 and 2.9

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