Probability of 3 out of 4 independent events occurring
I have 4 golfers playing together in a foursome. I know the probability of each making a par or better on a given hole:
A-player: 60%
B-player: 50%
C-player: 40%
D-player: 30%
What is the probability that any three of these 4 golfers will make par or better on the hole?
ANSWER: Need help on how to calculate this. Is it just adding together the four probabilities of the possible outcomes where 3 players shoot par or better? Namely: P(A&B&C)+P(A&B&D)+P(A&C&D)+P(B&C&D) = .12+.09+.072+.06 = 34.2%. Is this it or am I missing something?