Dear experts,
How do I create a dos batch file to copy only todays(current date) files from the directory.

You would need to batch files.

First one:

Code:

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@echo off
set /p destination="Destination: "
for /f %%a in ('dir') do call copyFile.bat %%a %%~ta %destination%

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Second one (this is where I start getting confused):

Code:

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@echo off
set today=%date:~5,15%
if %today% == %2 copy %1 %3

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From what I can tell, that should work, but it doesn't quite work right. Think you can get it from there?

Quote:

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How do I create a dos batch file to copy only todays(current date) files from the directory.

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Here is a script. (I am assuming that when you say today's files, you mean files modified today.) It starts in directory "dir1". It copies files to "dir2" .

Code:

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var str today ; set today=gettime()
cd "dir1"
var str list ; lf -n "*" ( ($fmtime >= $today) AND ($fmtime <= $today) AND ($ftype=="f") ) > $list
while ($list <> "")
do
    var str file ; lex "1" $list > $file
    system copy $file "dir2"
done

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Script is in biterscripting ( http://www.biterscripting.com ) .

Patrick

How do I create a dos batch file to copy files into current date folder