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    samantha96's Avatar
    samantha96 Posts: 1, Reputation: 1
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    #1

    Sep 16, 2010, 06:28 PM
    Algebra 2 answers
    The second of three numbers is 4 times the first number. The third number is 12 less than the first. Find the three numbers given that there sum is 42
    Kitkat22's Avatar
    Kitkat22 Posts: 6,302, Reputation: 1191
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    #2

    Sep 16, 2010, 06:39 PM

    There is a homework forum here.
    Someone can help you with this.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #3

    Sep 17, 2010, 08:40 AM

    Let the three numbers be A, B and C in this order.

    You are told that B is 4 times A. That is B = 4A
    Then C is less than A by 12. So, C = A - 12
    You are also told that their sum is 42. So, A + B + C = 42.

    Can you solve for A, B and C now? :)
    Kitkat22's Avatar
    Kitkat22 Posts: 6,302, Reputation: 1191
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    #4

    Sep 17, 2010, 08:43 AM
    Quote Originally Posted by Unknown008 View Post
    Let the three numbers be A, B and C in this order.

    You are told that B is 4 times A. That is B = 4A
    Then C is less than A by 12. So, C = A - 12
    You are also told that their sum is 42. So, A + B + C = 42.

    Can you solve for A, B and C now? :)



    Wish I had your brain... I have no clue to that problem... Your good , my man.. good.:D

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