Just going to post the math.

You start with 6 ounces in each glass. You move one ounce of red into the white.

The white glass now has 6 ounces white and 1 ounce red. The red glass has 5 ounces red.

Then you move one ounce back. This one ounce contains 1/7 ounce red and 6/7 ounce white. (the proportions that are in the white glass)

So, subtracting this from the white glass we have 6/7 ounce red and 5 1/7 ounce white.

Adding to the red glass we have 5 1/7 ounce red and 6/7 ounce white.

They are both contaminated by the same amount! It's unintuitive until you actually do the math :)

Um I would say that the one that was originally all red was contaminated more.

(psst check the solution above your post) :)

OK capuchin. The way I dd it it cam eout that the red was more contaminated but whatever.

Can you see a flaw in my working? I'd like you to point out where I am wrong.

Ah, Capuchin. You are mathematically correct. But given that red wine is far superior to white, wouldn't the white glass be 5 1/7 ounces contaminated with only 6/7 ounces of good?:p

Isn't this question from forever ago? I remember this from when I first started I think. ;)

No need to get mad capuchin. In my weird mind it cam eout the red is more ontaminated. Bbut you are probably corredt. I don't wish to work it out write now. I got it wrong. Oh well.

Contami- wha? HEY! The glasses are empty *BURP* whooo! Uh, they are both comtomintated he he he he *falls over*