I don't know it keeps showing me these weird symbols its suppose to be

x^2=2yv-z
2yv=x^2+z
v=(x^2+z/2y
4.11

1. Yes, the answer I got is 11.47.

2. No, I'm getting something totally different here... though you worked it out well.

That would give me 0.00017 as the answer... Is that right

Hmm, I'm sorry, but this is not what I am getting, unfortunately.



All right? A little easier like that?

okay 7.45/7.0 then you subtract the powers so it becomes 10^-3... which would give you 1.0642 *10^-3 =0.001064 is that right ?

That's what I got :)

hi
can you check this for me
4ac^2=c^2+3ab when a=4.5 and b=3.6. make c the subject

4ac^2=c^2+3ab when a=4.5 and b=3.6
4*4.5*c^2 = c^2 + 3*4.5*3.6
18c^2 = c^2 + 48.6
17c^2=48.6
c^2 = 48.6/17

c = +/- sqr(48.6/17) = +/-1.6908

Yea you can do it like that, but this defeats the purpose of making c the subject... :(

Start by moving c^2 on the left side, then factor c^2.

okay so
4ac^2 = c^2+3ab
4(4.5)c^2 = c^2 + 3(4.5)(3.6)
18c^2 = c^2 + 48.6
17c^2 = 48.6
c^2 = 48.6/17
c^2 = 2.86
c = 1.69

No no no. You don't put in the numbers until you have c as the subject.





Forget the values of a and b for the time being and make c the subject of formula.

c^2=4ac^2+3ab is this arrangement right ?

No, you have c^2 on both sides...

Take from the last line in my previous post. Factor out c^2 just like you would factor x here:

ax - 2x = x(a - 2)

hi
I tried it and this is what I got. :-)

4ac² - c² = 3ab

=> c²(4a - 1) = 3ab

=> c² = 3ab/(4a - 1)

c = √(3ab/(4a - 1))

4ac² - c² = 3ab

=> c^2(4a - 1) = 3ab

=> c^2 = 3ab/(4a - 1)

c = squr(3ab/(4a - 1))

sorry it suppose to be
4ac^2 - c^2 = 3ab
I don't know why it keeps showing these weird symbols

Type them manually instead of copy/pasting from Microsoft word or something, but if I understood it well, you did a good job! Replacing the values of a and b in the last equation you got, that is:



You should get c as 1.69 :)