How can I find the area of the inner circle and the area of the large outer circle ?

Joe's centrepiece is a simple but very effective use of two circles and

Two regular hexagons rotated to give the effect of a medieval dial. The

Radius of the inner circle is 10 cm, half the length of the sides of the

Regular hexagon. AC is a side of one of the hexagons and BD is a side

Of the second, which is obtained from the first by rotation.

(I) Find the area of the inner circle, giving your answer in terms of π.

(ii) Find the area of the large outer circle also in terms of π and

Hence express the area of the inner circle as a percentage of the

Area of the large outer circle.

Hint: Each hexagon can be divided into six congruent equilateral

Triangles, for example the triangle AMC is one of the six

Equilateral triangles that make up one hexagon and the triangle

BMD is one of six equilateral triangles that make up the second

Hexagon.

Comment on ebaines's post

LOL. Guess you already beat me to it.