Ha ha yes! She hasn't had a math class since '99

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Originally Posted by Romefalls19

ha ha yes! She hasn't had a math class since '99

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Hmmm, I haven't had one since 1964.

You're a teacher though, you cheated lol :p

Quote:

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Originally Posted by Romefalls19

Your a teacher though, you cheated lol :p

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I haven't taught school (math) since the late '70s. After that I taught preschool. I've been a librarian since 1984--and cataloger for fifteen years ('cause I'm darn good with numbers).

What about creating the real-life problem with linear equations?

Lol I just work on computers

For the real-life problem, whip up a word problem for recarpeting your hallway. The problem will be much like the rectangular field one. Use the area dimension of the hallway as a total instead of perimeter, to make it different from the field one.

I have to leave to eat supper, so please post your word problem and the solution and answer. I will check in a half hour or so.

How does this sound?

You are carpeting your hallway and need to know how much carpet to purchase. After measuring you realize that the hallway has a perimeter of 60 feet and that the length is 10 feet more than the width. Find the length of the sides.

The answer is:
x=10
Length of each side is 20
Width of each side is 10

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Originally Posted by Romefalls19

How does this sound?

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I'm back.

How was dinner?

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Originally Posted by Wondergirl

You can see it better if you draw a picture. Slap the person who yelled at you.

Draw a picture--a rectangle--then note on each side the values assigned.

(I figured it out ten minutes ago.)

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LOL, I just had to read it to figure it out.

Quote:

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Originally Posted by Romefalls19

ha ha yes! She hasn't had a math class since '99

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I hadn't had math since 1980. It slowly comes back. NEvER had to have Algebra until 2004... was totally lost.

Quote:

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Originally Posted by Romefalls19

How does this sound?

You are carpeting your hallway and need to know how much carpet to purchase. After measuring you realize that the hallway has a perimeter of 60 feet and that the length is 10 feet more than the width. Find the length of the sides.

The answer is:
x=10
Length of each side is 20
Width of each side is 10

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How about:

You are carpeting your hallway and need to know how much carpet to purchase. After measuring, you have found that the hallway has a perimeter of 60 feet. The length of the hallway is ten feet more than the width. What are the dimensions of the hallway? How many square feet will you need for carpet?

width = x
length = x + 10
perimeter = x + x + x+10 + x+10 = 60
area = ? (x * x+10) sq ft

Dinner was leftover cold fried chicken from Brown's, a Chicago franchise. Also, Hawaiian Punch on ice and two homemade brownies. *burp*

Width = 10
Length = 20
x=10
Area = 200sq ft?

Quote:

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Originally Posted by Romefalls19

Width = 10
Length = 20
x=10
Area = 200sq ft?

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Yes!!

Thank you so much for all of your help!

Don't forget to solve with these linear equations:

width = x
length = x + 10
perimeter = x + x + x+10 + x+10 = 60
area = ? (x * x+10) sq ft

Yep we did! Now we can relax and spend the night together!