Well, let's see the dress!

Quote:

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Originally Posted by Aurora_Bell

well, let's see the dress!

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And it's only 185!
It's the dress I've dreamed of since I was a little girl

Since I can't get married in pure white since I'm not a virgin, I decided you know what, it may be red but it's beautiful. And I've always dreamed of a blood red wedding dress

Next step, using the statement

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

We know that A = 5, hence, there is 5C

where C is either 2 or 6.

Using the next statement 'The 3-digit number ACB is divisible by 3'

We know that A + B + C is divisible by 3. So,
if C = 2, B = 2, 5 or 8.
if C = 6, B = 1, 4 or 7.

Then, using 'CBA has an odd number of factors'
We have either of:
225, 255, 285, 615, 645, 675

From those, we try each of them until we get an odd number of factors.

Very pretty dress Emop.

Quote:

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Originally Posted by Unknown008

Next step, using the statement

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

We know that A = 5, hence, there is 5C

where C is either 2 or 6.

Using the next statement 'The 3-digit number ACB is divisible by 3'

We know that A + B + C is divisible by 3. So,
if C = 2, B = 2, 5 or 8.
if C = 6, B = 1, 4 or 7.

Then, using 'CBA has an odd number of factors'
We have either of:
225, 255, 285, 615, 645, 675

From those, we try each of them until we get an odd number of factors.

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That's waaay too many numbers, it makes my brain hurt just looking at it!

Quote:

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Originally Posted by xXxEmOxXxPrInCeSsxXx

and it's only 185!
it's the dress I've dreamed of since I was a little girl

Since I can't get married in pure white since I'm not a virgin, I decided you know what, it may be red but it's beautiful. and I've always dreamed of a blood red wedding dress

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Well, apart from the idea of the blood red coloration... it's beautiful!

Okay Bella, I'll stop :o

Thanks guys

And Please Unky! No more brain ouches

I said I'll stop :(

Aww it's okay Unky, we're just jealous because we aren't as smart as you!

Ok, I'm tired now, see you all!

Night Unky!

Wearing white on your wedding day doesn't signify virginity, it just signifies your first marriage.

A veil signifies virginity.

Just saying.

Quote:

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Originally Posted by redhed35

bloody hell heath!

perhaps you were over tired to start with or your coming down with something.

we would have missed you here and sent out a search party.

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I'm not really sure, but it kind of sucks knowing I almost died last night.

Quote:

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Originally Posted by Unknown008

Nah, since there are still problems that I can't solve :o

Ok, for example this one:

Quote:

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A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

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I didn't solve it and had to view the solution... :(

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OK, so B can be pretty much any digit. C must be an even number. A must be either 5 or 0.

since a 3-digit number cannot start with 0, none of the digits can be 0, which mean A must be 5.

5CB must be divisible by 3, while B5C must be divisible by 4. since C must be even, that leaves us with 2, 4, 6, or 8. B can be any digit but 0 at this point.

let's try A=5 B=1 C=6.
561/3=187
156/4=39
165/5=33
the only way for a number to have an odd number of factors is if it has a whole number as the square root. The square root of 516 is 22.71, so it's not our answer.

OK, so, let's try A=5 B=4 C=6
564/3=188
456/4=114
465/5=93
the square root of 546 is 23.36, so it's not our answer, either.

A=5 B=5 C=8
585/3=195
558/4=139.5 which eliminates that as a possibility

A=5 B=8 C=8
588/3=196
858/4=214.5 which eliminates that, too

OK, I'm at a loss.

Quote:

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Originally Posted by Unknown008

Next step, using the statement

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

We know that A = 5, hence, there is 5C

where C is either 2 or 6.

Using the next statement 'The 3-digit number ACB is divisible by 3'

We know that A + B + C is divisible by 3. So,
if C = 2, B = 2, 5 or 8.
if C = 6, B = 1, 4 or 7.

Then, using 'CBA has an odd number of factors'
We have either of:
225, 255, 285, 615, 645, 675

From those, we try each of them until we get an odd number of factors.

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Doh I missed the obvious that a 3 digit number cannot begin with A being 0 so A is 5. Does having the flu count as a good excuse for being dim lol?

225 it a perfect square - odd number of factors. So A = 5, B= 2, C=2.

Quote:

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Originally Posted by xXxEmOxXxPrInCeSsxXx

here is my ring and the place he's proposing

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Gorgeous ring! :)

Quote:

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Originally Posted by hheath541

I'm not really sure, but it kinda sucks knowing i almost died last night.

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Are you feeling even better from earlier today?

I have rivers of sweat running of me, this flu is making me a right old minger. ><.

Hope you are able to get some rest QLP and feel better soon. Anything like Lemsip or tea helpful?

Hey Hheath, hope you are feeling better. But you know, heat stroke is just another excuse to strip nakkie and spray yourself down with water... juts sayin'...