No... Maybe unequal since she or he stirred it.
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There is more white in the white.
If 5 mL of white was moved to the red, it was undiluted.
If 5mL of the red with white was moved over to the red, it wasn't 5mL of red.. it was mostly red, but a little white back.
More white is in the white.
***edited... proved to be wrong in my later posts***
Oops. Crap. wrong.
What worked in my head is wrong on paper.
First... you must assume that both transfers are equal in volume... that exactly the same volume was moved in both cases.
Then...
Lets pretend we have 100 mL of each wine in two glasses.
You take out 5 mL of white to the red. That's 105 mLs of wine in the "red" glass, 100 mL red with 5 mL white. Its 95.238% red.
Then you take 5 mL of this mixture to the white.
You add to 95 mL white 4.762 red and 0.228 mL white... for a total of 100 mL wine, but the composition is different... its just 95.228% white...
The reason is you are adding a mostly red aliquot to a lesser volume of white. The lesser volume of white is what got me mentally.
Pooh.
Shouldve done the math first.
My head hurts.
Can we do an English riddle/problem? Math is not my strong point, and no, I'm not willing to learn. ;)
So... I was wrong at first... the red is more red percentage wise.
Unless the transfers weren't perfectly equal. Forgot to ask if a proper dialed pipette was used.
The stirring ensures consistent concentration.
If I add a little something to a lot of something else and don't stir, I cannot take a sample of it and have it be representative of the whole.
Anyone who was worked with analytical chemical glassware knows they must mix and mix and mix to ensure proper, uh, mixing... and therefore, consistent concentration throughout the sample, no matter where you sample.
The only thing I know is that I now want a glass of wine. I don't care if it's shaken, stirred, or mixed, I just want it in a glass. :)
I assume they started with the same volume. Without that assumption, this is just unanswerable.
but when you take out 5 mL from one and put it in the other... the original white now has just 95 mLs.
I know its hard to get.
I'm good at this stuff and my instinct answer was off.
if all the reasonable assumptions are right... equal starting volumes and equal transfers, the math is the bottom line. White wins for higherst % by a smidge.
if the assumptions are wrong... k... too many variables for my liking.
Okay, either it is too late and my one glass of wine did me in (not unusual), or you have a slight math error.
I worked it out as follows:
You start with 100 ml of white and 100 ml of red.
5 ml of white is moved to the red, so you now have 95 ml of white, and 100 ml of red with 5 ml of white added.
If you take 5 mil of this mix, 4.762 ml (=100/105*5) will be red and .238 (=5/105*5) ml will be white. This gets added to the 95 ml of white.
The original white is now (95 ml+ .238 ml) 95.238 ml white and 4.762 ml red.
The red mixture is now (100 ml-4.762 ml) 95.238 ml red and (5 ml-.238ml) 4.762 ml white.
They are equal.
In looking at your numbers, when you add the 5 ml to the 95, the correct numbers should be 4.762 and .238. It looks like a math error – as 4.762+.228 does not equal the 5 ml you are transferring, or another way to look at it is 95+4.762+.228= 99.99, not 100.
Please tell me I haven't embarrassed myself. :o
I just want to know where my wine is! ;)
If it takes ten men 3 hours to dig one hole, how many men does it take to dig half a hole in the same amount of time.
Give up? It's really a dumb riddle.
You can't dig half a hole! It would just be a different sized hole
I know - dumb. Somehow it made me giggle... it's that one glass of wine. I'm such a cheap date. :p
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