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Add solute, dilute to the mark and you know the amount of solute and the amount of solution. In other words you know the concentration. With moles per gram you know the molality, but this is a narrowly useful unit,(as far as I remember its only used for freezing and boiling point work.) And 3 mol/18g and .167 mol/g are WAY to concentrated for the real world, (That's 58.5g 0f NaCl in 18ml of water. It will be a paste, not a solution!

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Great!

In short, molarity is mol/dm^3 or mol/L and molality is mol/g. (just to confirm)

And yes, I suspected it was no more a solution but a paste now, hence my side note to disregard solubility :)

Except that now... I can't leave a 'thumbs up' or 'greenie' to a comment =/...