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  • Oct 28, 2009, 03:06 PM
    Identify any nonionic, or insouble products and.
    Write balanced net ionic equations for the following reactions.
    Identify any nonionic, or insouble products and determine which reaction(s) is (are) oxidation-reduction reaction.

    a. HCl(aq)+LiOH(aq)-->H2O(l)+LiCl(aq)

    b. Zn(s)+2HCl(aq)-->ZnCl2+H2

    c. Na2CO3+2HNO3-->2NaNO3+H2O+CO2
    3 +2H+-->H2O+CO2

    Can you check these balanced net ionic equations(underlines equations) are correct or some problems are in these...

    Also help me that Identify any nonionic, or insouble products and determine which reaction(s) is (are) oxidation-reduction reaction.

  • Oct 29, 2009, 08:38 AM

    Well, do you know that 'nonionic' compounds are called 'covalent' compounds?

    In fact, in these compounds, there is a sharing of electrons, which in contrast with ionic compounds, does not lead to the formation of ions.

    Look for the compounds which you cannot break into a cation (ion with positive charge) and into a cation (ion with negative charge). Those will be the nonionic compounds.

    I guess you can find the insoluble products, whose which escape as gases, or become liquids, or become solids. The state symbols here will help you identify those.

    A redox reaction is one whereby a element has different oxidation states before and after the reaction. Ionic compounds have an oxidation state equal to their charge. Elements in covalent compounds are considered to to have an oxidation state of zero.

    Post your answers! :)
  • Oct 29, 2009, 01:04 PM
    I think B is nonionic..
  • Oct 29, 2009, 10:56 PM

    You have to look for the nonionic products, not equations and redox equations.

    For (a) Non ionic = H2O, it is a redox reaction because H+ had an oxidation state of +1 at first, then it became 0 and OH had an oxidation state of -1, then it became 0.

    Try for the other two :)
  • Oct 30, 2009, 02:24 PM
    b) doesn't have nonionic... I think

    c) H2O is nonionic right?

    Please help me and you always thank you so much
  • Oct 30, 2009, 11:37 PM

    B) You have Zn^2+ and H2.

    H2 cannot be written as H^+ and H^- here, and is therefore non ionic.

    C) Yes, H2O is non ionic, as it is the case in A). CO2 is also non ionic.

    And which one do you think is a redox reaction? Where you have an ion becoming a covalent (non ionic) compound?
  • Oct 31, 2009, 03:59 PM
    I think A) is redox reaction
  • Oct 31, 2009, 04:06 PM
    I think a,b,and c are all soluble products

    Isn't it?

    And I am confusing that which reaction is oxidation reduction reaction.

    Please help me Thanks!!
  • Nov 1, 2009, 03:30 AM

    Yes, A is a redox reaction

    B too is a redox reaction, since Zn (ON 0) goes to Zn^2+ (ON +2) and H^+ (ON +1) goes to H_2 (ON 2).

    [ON = Oxidation Number]

    Here, Zn is oxidised and H^+ is reduced.

    Oxidation is an increase in oxidation number and Reduction is a decrease in Oxidation number.

    C now, can you guess using the things I just taught you?


    In A, you have water. Do we say that water is soluble in water? Lol! No!

    In B, you have Zn^2+. Have you done the famous reaction of copper (II) sulfate and zinc metal yet? If so, you'll see that the zinc dissolves and a brown metal is deposited on the zinc lumps, while the blue colour of the solution fades to colourless. This means that Zn^2+ is soluble in water.

    H2, however is not soluble in water, and the actual reaction of zinc plus acid is for the production of hydrogen gas. The gas is bubbled through water so that is can be collected. That means that hydrogen must be insoluble in water, or else, it wouldn't have been bubbled through the latter to be collected.

    C. Carbon dioxide is only slightly soluble in water. So, my answer in that case would be that carbon dioxide is insoluble in water.
  • Nov 1, 2009, 11:53 AM
    I think C is redox reaction too,
  • Nov 1, 2009, 10:20 PM

    Yes! You have H^+ going to H2O which means its ON decreased from 1 to 0!

    Then, you have CO3 ^2- going from ON -2 to 0 in CO2.

    Well done! :)

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