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Arian 23
Jun 19, 2012, 09:59 PM
cscx=cotx+tanx/secx

ebaines
Jun 20, 2012, 06:10 AM
cscx=cotx+tanx/secx

Your equation is incorrect:


csc x \ne cot x + \frac {tan x}{sec x}


However, if you meant this:


csc x = \frac {cot x + tan x}{sec x}


all you need do is convert the tan, cot, sec, csc functions to their sine and cosine equivalents and simplify the resulting fraction. And remember rhat cos^2x + sin^x = 1.