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thunderboymmt
Oct 8, 2009, 08:22 PM
Diketones are classified according to the-
Options are-
1) O
2) C
3) -CO
4) -CO2

Please explain

ROLCAM
Oct 8, 2009, 11:30 PM
Diketones are classified according to-? - Yahoo! Answers
1) O-atom 2) C-atom 3) -CO-atom 4) -CO2... 3) -CO-atom. Diketones have two carbonyl groups in their molecular structure, hence the "di" in their name.. .

answers.yahoo.com/question/index?qid=20091008092129AA6rYFi

Have a good look at this site.

ROLCAM
Oct 8, 2009, 11:34 PM
Diketone - Wikipedia, the free encyclopedia
28 Feb 2009... A diketone is a molecule containing two ketone groups. The simpliest diketone is diacetyl, also known as 2,3-butanedione.. .

En.wikipedia.org/wiki/Diketone

Have a look at this site.

thunderboymmt
Oct 8, 2009, 11:41 PM
Your post doesn't answer my question.

ROLCAM
Oct 8, 2009, 11:43 PM
SEE ALSO:-

DIKETONES - Online Information article about DIKETONES (http://encyclopedia.jrank.org/DEM_DIO/DIKETONES.html)

Perito
Oct 9, 2009, 09:10 AM
Diketones are classified according to the-
options are-
1) O
2) C
3) -CO
4) -CO2

please explain

Ketone - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Ketone)

Diketone - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Diketone)

A diketone is simply a molecule with two ketone groups. A ketone is a carbon atom attached to two adjacent carbon atoms and containing a C=O (carbon double-bonded to an oxygen). The Wikipedia pages shows drawings. The C=O group is the most important thing.

There are other molecules with CO groups in them. Aldehydes, and carboxylic acids. The difference is that the carbon aldehyde is bonded to only one carbon and to one hydrogen atom.

Aldehyde - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Aldehyde)

In a carboxylic acid, the carbon is bonded to one carbon and to one hydroxyl (OH) group.

Carboxylic acid - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Carboxylic_acid)

Can you figure out your question now? I would have preferred that there were two lines connected to the carbon

"=CO" or maybe more preferably ">CO"