Simplify radcial expressions:


1. (2+squareroot5) (3-squareroot5)






2. 3 squareroot 48 - 2 squareroot75
_______________________________
Squareroot 12

I will step you through the last one to show you how. Then you apply it to others. OK?

\frac{3\sqrt{48}-2\sqrt{75}}{\sqrt{12}}

\frac{3\sqrt{16\cdot{3}}-2\sqrt{25\cdot{3}}}{\sqrt{4\cdot{3}}}

See how we have \sqrt{3} common to all the terms? Those are the kinds of patterns we look for.

\frac{3\sqrt{16}\cdot\sqrt{3}-2\sqrt{25}\cdot\sqrt{3}}{\sqrt{4}\cdot\sqrt{3}}

\frac{12\sqrt{3}-10\sqrt{3}}{2\sqrt{3}}

\frac{2\sqrt{3}}{2\sqrt{3}}=1

And that's it. Whittled down to a very simple answer. Now, you try on the other.

3 squareroot 5 + 5 squareroot 6 + 3 squareroot 20