Quote:
2. After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it reaches Julie's horizontal position. Assume the ball leaves Sarah's hand a distance 1.5 meters above the ground, reaches a maximum height of 14 m above the ground, and takes 2.592 s to get directly over Julie's head. What is the speed of the ball when it leaves Sarah's hand?
Okay, so first of all we need to know how far apart Julie and Sarah are standing. Luckily we can get the answer from the information given in Part 1. You solved for the time, t, when Sarah caught the ball. You also know the horizontal component of the velocity was 24*cos(34) = 19.897 m/s. So now we can compute the horizontal distance between the two girls as