Can someone explain to me how to solve this equation:
(4/9)-1/2*
*Exponent
??
Can someone explain to me how to solve this equation:
(4/9)-1/2*
*Exponent
??
(4/9)-1/2*Quote:
Originally Posted by Slimboyie
= (9/4)1/2*
= Square root of (9/4)
= (Square root of 9)/(Square root of 4)
RULE:Quote:
Originally Posted by Slimboyie
a^(-b) = 1/a^(b)
We can use this rule to solve your negative fractional exponent question.
4/9 raised to the negative fraction -1/2 becomes 1/(4/9)^(1/2)... Notice that the fraction 1/2 became POSITIVE when moved to the right side of the equation. See it?
Our denominator--->this guy--> (4/9)^(1/2) can be written as a square root. We now have the square root of 4/9, which 2/3.
Our new fraction is 1/(2/3).
What is 1 divided by 2/3?
Final answer: 3/2.
(x^(1/2)-2x^(-1/2))/(x^(-1/2))
bryndle - please do not tag a new question onto an old thread. Instead you should start a new question. But to help out...
Remember that:
For example:
can you take it from here?
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