qn 3d
r=(I+7j-5k)+(lambda)(3i-j-2k)
find the ratio AC:CB
co-ords of A -5,9,-9 B 25,-1,11 C 4,6,-3
I thought I could do (-5+9-9)*(4+6-3):(4+6-3)*(25-1+11) and workout the ratio that way I get 1:7
but mark scheme gets 3:7 how and why
5a, for the last part of the table when x=2 I always get y=0.766 y=4(x^0.5)e^-x
mark scheme gets 1.083
qn 6)find the integral of 2sin3x sin2x dx I tried parts but went wrong some where
Andrew Cropley