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  • Dec 2, 2009, 08:28 PM
    vanityb
    free algebra 2 answers
    Okay I'm Performing Operations with Complex Numbers and its prety confusing to me I have this equation and its somthin to have to do with imaginary numbers my equation is (6-3i) + (5+4i)
  • Dec 2, 2009, 08:36 PM
    ROLCAM

    1) (6-3i) + (5+4i)

    2) 6 - 3i + 5 + 4i

    3) 4i -3i = -6 - 5

    4) I = -11
  • Dec 3, 2009, 03:44 AM
    Unknown008

    Uh... do you mean: ?

    Because an equation has to have an equal sign, which I don't see in your question. What you gave is called an expression. Anyway, if it's like you said, then that's what you have to do:



    And that's all. 11 is the real part, and i is the imaginary part.
  • Dec 3, 2009, 09:08 AM
    KISS

    rolcam:

    I = sqrt(-1); a mathematical concept. Electrical Engineers use j rather than I to represent the same concept.

    5+3i is an example of the rectangular form of a complex number. 155 @ an angle of 90 deg is the polar form/
    Usually the "@ an angle" is written as a symbol that looks like a < sign laying on it's bottom side.
  • Dec 3, 2009, 09:15 AM
    Unknown008

    Or we use the trig form like

    or in Euler's form

    if my memory is good. Arg, I have to revise!! :(

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