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n^{log{\small_2}n}^{log{\small_2}n} ={n^{log{\small_2}n}}^{log{\small_2}n} ={{n^{(log{\small_n}2)}}^{-log{\small_2}n} ={ 2^{(log{\small_2}n)}}^{-1} = \frac{1}{n}
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