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askforhelp22 · Oct 13, 2008, 09:58 PM

Dim number1 As Integer
Dim number2 As Integer
Dim result As Integer

number1 = (4 * 6 ^ 4) / (10 Mod 4 - 2)
number2 = (16 \ 3) ^ 2 * 6 + 1
result = number1 - number2

askforhelp22 · Oct 13, 2008, 10:13 PM

Can someone answer this please?

devonknows · Oct 23, 2008, 02:14 PM

Originally Posted by askforhelp22

Dim number1 As Integer
Dim number2 As Integer
Dim result As Integer

number1 = (4 * 6 ^ 4) / (10 Mod 4 - 2)
number2 = (16 \ 3) ^ 2 * 6 + 1
result = number1 - number2

Have you tried

number1 = CInt(4 * 6 ^ 4) / CInt(10 Mod 4) - 2

As the division by zero comes in when you insert the -2 into the brackets.

I used this code

Code:

number1 = CInt(4 * 6 ^ 4) / CInt(10 Mod 4) - 2
number2 = (16 \ 3) ^ 2 * 6 + 1
result = number1 - number2

MsgBox result

and got an answer of 2439. Unsure if that is the answer you are looking for.

Devon