cari1966 Posts: 8, Reputation: 1 New Member #1 Jul 9, 2012, 11:04 AM
find the probabilty events
Let s={1,6,11,16,21,26}, E={6,16,26}, and G={21,26} Find the event E F AND G. Upside down u in between each letter. If there are no elements in the set, enter NONE
 ebaines Posts: 12,130, Reputation: 1307 Expert #2 Jul 9, 2012, 11:08 AM
The Upside down u" is the "and" symbol $\cap$, so you are looking for any elements that are contained in all three sets - are there any? And though you called the first set "s" I think you meant "F," correct?
 cari1966 Posts: 8, Reputation: 1 New Member #3 Jul 9, 2012, 03:35 PM
Originally Posted by ebaines
Teh
Upside down u" is the "and" symbol $\cap$, so you are looking for any elements that are contained in all three sets - are there any? And though you called the first set "s" I think you meant "F," correct?
I left out the f={1,11,21}. So would the answer be 21,26 or does it mean included in all E,F,G which would be none,because there is none that are in each one?
 ebaines Posts: 12,130, Reputation: 1307 Expert #4 Jul 10, 2012, 07:35 AM
if F={1,11,21} then it has no common elements with E={6,16,26}. So the intesection of $E \cap F$ is the null set.

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