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Smoothy - this does not sound like a homework question to me - it's a bit off the wall.
To the OP: free neutrons can't be contained like water in a glass. Since they are neutral charge you can't build a "magnetic bottle" or other device to constrain them separate from the container they're in. Generally what happens is the free neutrons pass into the material of the container and ultimately are absorbed within the nuclei of atoms that make up the container, and thus create alternative isotopes of that material (which may make the material radioactive). |
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Electricity
Obviously a piece of copper wire can only hold so much electricity, what is the ratio for the amount of electricity to the width and distance of wire ? Would the ratio of electric to wire change for different types of wire ?
How can the above information be used to make a transformer ? In a transformer the copper wire is turned round steel plates, why are the steel plates there ? |
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A wire doesn't "hold" electricity the way a pipe holds water, if that's what yuo're thinking. Wires carry current, whichis the flow of electrons. A coper wire is a very good conductor compared to, say, a piece of wood, so electrons can flow through a copper wire much more easily than throufgh a piece of wood. The ability of a wire to carry electric current is called conductance, and in general the higher the conductance the less loss of power ter is due to resistive heating. The conductance of a piece of wire is proportional to its cross-sectional area (at least for low frequency applications), so if you double the diamater of the copper wire it can carry 4 times as much current with the same amount of loss. Other metals such as steel or aluminum can be used for wire, with some difference in conductance for each material.
As for transformers: the steel (actually iron) plates in a transformer are known as the core - they serve to carry magnetic fields between the windings of the transformer. The way a transformer works is the alternating current in one coil creates a magnetic field insde the coil, the strength of which depends on the number of turns of wire in the coil; the iron loop inside that winding picks up the magnetic filed transfers it to inside the second coil, and there the varying magnetic field induces a voltage into the second winding, the volatege of which is dfependent on the number fo turns of wire of the 2nd coil. The ratio of voltages between the first and second coil works out to be equal to the ratio of the number of windings between the first and second coil. In this way AC voltages can be stepped up or down through the transformer. |
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Behaviour of electricity
If there where a single strand of 0.9 copper wire at a length of 1cm how much current could potentially occupy the surface ? Would this double if the length of the wire doubles ?
How do the soft iron (mild steel) plates effect a transformer ? |
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Current carrying capability of a wire is not affected by length. The current capacity of a 0.9mm diameter copper wire (about 19 AWG) is about 10A. This assumes low frequency current. You mentioned capacity of the surface of the wire - why? Are you considering high frequency AC current? (several megahertz or higher)? Electrons generally flow through the core of the wire, but may be limited to the surface if the frequency is high.
I addressed the function of the core in your other post. See: https://www.askmehelpdesk.com/physic...ty-783606.html if you have additional follow up questions it's better to post the question in the original thread as opposed to starting a new thread. |
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A coil used in generating
If there where a coil next to a rotating magnet (1500)rpm ,
The core of the coil is 15mm long 16mm depth and 5mm width with 2 meters of 0.9 enameled copper wire wound around it, how much electricity would it produce per pass of the magnet? and how (please with calculus with explanation of calculus) would one work it out ? |
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 Originally Posted by hello94857
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