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    computerk8t's Avatar
    computerk8t Posts: 1, Reputation: 1
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    #1

    Feb 17, 2013, 11:09 PM
    I am of an age between 10 and 100. I noticed that when I write my age in hexadecimal
    I am of an age between 10 and 100. I noticed that when I write my age in hexadecimal (base 16) the digits are in reverse order of my age in decimal (base 10). How old am I?
    JudyKayTee's Avatar
    JudyKayTee Posts: 46,503, Reputation: 4600
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    #2

    Feb 18, 2013, 06:53 AM
    Been posted before. I assume this is homework?

    https://www.askmehelpdesk.com/mathem...gi-514434.html

    Why did you post under computers for beginners?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #3

    Feb 18, 2013, 06:56 AM
    Here's how to solve it: lin base 10 let A be the units digit and B the ten's digit, i.e. your age in base ten is 'BA.' Then in base 16 your age is 'AB.' Making these equal means:

    10B + A = 16A + B

    Rearrange:

    9B = 15A

    Since both A and B are integers this means 15A and 9B are each multiples of both 15 and 9. What numbers can you think of that meet that requirement? Once you have it, then you can solve for the values of A and B.
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