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    scoren76's Avatar
    scoren76 Posts: 3, Reputation: 1
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    #1

    Oct 17, 2012, 05:13 AM
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    I have $100 to buy 100 animals. 1 cow costs $5, 1 sheep costs $1 and 1 pig costs 5 cents?
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
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    #2

    Oct 17, 2012, 05:18 AM
    Do you have a question then?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #3

    Oct 17, 2012, 05:56 AM
    There are two solutons to this, where you spend precisely $100 to buy precisley 100 animals. One of the answers is immediately obvious; the other less so.
    scoren76's Avatar
    scoren76 Posts: 3, Reputation: 1
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    #4

    Oct 17, 2012, 04:13 PM
    Its an algebra question, its 20 years since I done algebra. The question is already there, a hundred dollars to buy a hundred animals and the prices are there, and you have to have 1 of each.
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    scoren76 Posts: 3, Reputation: 1
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    #5

    Oct 17, 2012, 04:16 PM
    Quote Originally Posted by ebaines View Post
    There are two solutons to this, where you spend precisely $100 to buy precisley 100 animals. One of the answers is immediately obvious; the other less so.
    Yes , you need to use all the money and buy at least one of each animal.. I just forget how to use algebra
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #6

    Oct 18, 2012, 05:45 AM
    You don't really need algebra, just logic. It's not that complicated. Think about this - if you buy any pigs at all you must buy then in multiples of 20, or else you can't get the total spend to be in whole dollars. And then the number of sheep you buy added to what you spent on pigs must come to a multiple of 5. So my suggestion is to see what happens if you buy 0 pigs, then try 20 pigs, Then 40, etc.up to 100. Like I said before - there are two solutions to this puzzle.

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