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    roysagz's Avatar
    roysagz Posts: 1, Reputation: 1
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    #1

    Sep 29, 2012, 12:36 PM
    algebra 1b - Equation for the number
    The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 63 greater than the original number. Find the original number
    teacherjenn4's Avatar
    teacherjenn4 Posts: 4,005, Reputation: 468
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    #2

    Sep 29, 2012, 03:54 PM
    What work have you done on this yet? First, come up with all the 2 digit numbers which have a sum of 9. I'll get you started: 18, 27... You continue the pattern, and see which one fits your problem. Post answer and we'll help you.
    retina111's Avatar
    retina111 Posts: 10, Reputation: 1
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    #3

    Oct 28, 2012, 06:54 AM
    Assume the number is XY. We know that X+Y = 9
    Also, the number is 10X + Y (since X is in tens place)
    If we reverse the digits, we have 10Y+X
    10Y+X = 10X + Y + 63
    Solving the equations we get the original number to be 18
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