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ccny_miah · Jul 31, 2012, 04:28 AM

republican democrat independent
male 46 39 1
female 5 9 0

1. randomly select one senator, what is the probability of getting a republican, given that a male was selected?

2. randomly select one senator, what is the probability of getting a male, given that a republican was selected?

3. randomly select 1 senator, what is the probability of getting a female, given that an independent was selected?

4. randomly select 1 senator, what is the probability of getting a democrat or independent, given that a male was selected?

5. randomly select 2 senators, what is the probability of getting a democrat female and a republican male?

Curlyben · Jul 31, 2012, 04:34 AM

So what do YOU think ?

ccny_miah · Jul 31, 2012, 04:42 AM

1. 46/86?

ccny_miah · Jul 31, 2012, 05:13 AM

Originally Posted by Curlyben

So what do YOU think ?

Is it correct?

ebaines · Jul 31, 2012, 05:47 AM

Originally Posted by ccny_miah

1. 46/86?

Correct - there are 46 republicans out of 86 males. Of course you can simplify that fraction.

What answers did you come up with for the other questions?

ccny_miah · Jul 31, 2012, 05:57 AM

2. 46/86?

ebaines · Jul 31, 2012, 06:01 AM

Originally Posted by ccny_miah

2. 46/86?

Correct numerator. But the denominator should be equal to the total number of republicans - what number is that?

ccny_miah · Jul 31, 2012, 06:27 AM

Originally Posted by ebaines

Correct numerator. But the denominator should be equal to the total number of republicans - what number is that?

I meant, 46/51.

ccny_miah · Jul 31, 2012, 06:32 AM

3. 0/1?

ebaines · Jul 31, 2012, 08:25 AM

Yes - answers for 2 and 3 are both correct. It seems you have the technique down nicely. Looking forward to seeing what you get for number 5.

ccny_miah · Jul 31, 2012, 09:34 AM

Originally Posted by ebaines

Yes - answers for 2 and 3 are both correct. It seems you have the technique down nicely. Looking forward to seeing what you get for number 5.

4. 39+1 over 46+39+1
40/86?

ccny_miah · Jul 31, 2012, 09:39 AM

And I don't get question 5. please help!

ebaines · Jul 31, 2012, 09:59 AM

Originally Posted by ccny_miah

4. 39+1 over 46+39+1
40/86?

Good.

ebaines · Jul 31, 2012, 10:11 AM

Originally Posted by ccny_miah

and i dont get question 5. please help!

To get a dem female (DF) and a rep male (RM) means you can either (a) select a dem female followed by a rep male, or (b) select a rep male followed by a dem female. The probabiliy of (a) is

$<br /> P (DF\ followed \ by \ RM)= \frac 9 {100} \times \frac {46}{99}<br />$

Note that the numerator of each fraction is the number of senators of appropriate persuassion, ane the denominator is the total number of senators to pick from.

Using this same technique you can calculate the probability of (b) - what do you get? Finally add $P(DF\ followed \ by \ RM) + P(RM \ followed \ by \ DF)$ to get the total probability.

ccny_miah · Jul 31, 2012, 10:51 AM

9x46/100x99= 23/550 therefore, (23/550)+(23/550)= 46/550. We can reduce to 23/275. The final answer should be 23/275. Correct?

ebaines · Jul 31, 2012, 11:03 AM

Originally Posted by ccny_miah

9x46/100x99= 23/550 therefore, (23/550)+(23/550)= 46/550. we can reduce to 23/275. the final answer should be 23/275. Correct?

Yes - correct!

ccny_miah · Jul 31, 2012, 11:15 AM

Thank you very much.

Question: the starting 5 players for the NY Knicks team have agreed to make charity appearance. If you must send 3 player to United Way event and the other 2 to Heart Fund event, how many different ways can you make the assignments?

ccny_miah · Jul 31, 2012, 11:22 AM

5! / (2)!(3)!= 10? Used the nCr formula.

ebaines · Jul 31, 2012, 11:27 AM

Originally Posted by ccny_miah

5! / (2)!(3)!= 10? used the nCr formula.

Yep.

ccny_miah · Jul 31, 2012, 11:39 AM

winning power ball lottery requires you to select 5 numbers between 1 and 53 inclusive and, in a separate drawing, you must also select the correct single number between 1 and 42 inclusive. Find the probability of winning the jackpot?