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    teddyw123's Avatar
    teddyw123 Posts: 3, Reputation: 1
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    #1

    Jul 17, 2012, 11:13 AM
    (tan(x))/(sec(x) 1) = (sec(x)-1)/(tan(x))
    I've been trying to prove the following identity:
    (tan(x))/(sec(x)+1) = (sec(x)-1)/(tan(x))

    For the left side, do you first have to multiply it by the conjugate?
    I've tried numerous times and my paper just ends up being a huge mess, please help!
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jul 17, 2012, 11:39 AM
    Convert the secant and tangent functions to their sine and cosine equivalents. Then you can simply by multiplying both sides by cos(x)/cos(x). Finally cross-multiply. What do you get?
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    teddyw123 Posts: 3, Reputation: 1
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    #3

    Jul 17, 2012, 12:00 PM
    sin(x)/(1+cos(x))
    on the left side

    and on the right side (1-cos(x))/(sin(x))

    so now on the left side do I do the conjugate?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Jul 17, 2012, 12:04 PM
    Cross multiply:

    If a/b = c/d then ad = because
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