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    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #1

    Jun 13, 2012, 01:21 PM
    7x=3x-80
    How do u do it and check it?
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #2

    Jun 13, 2012, 01:26 PM
    Please clarify your question.
    What are you trying to do ?
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #3

    Jun 13, 2012, 01:28 PM
    Quote Originally Posted by qwertyuioop View Post
    how do u do it and check it?
    I have 2 solve the equation and check my answer.
    And find what x is!
    Thanks if u answer it!
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #4

    Jun 13, 2012, 01:29 PM
    What have you done so far.
    Remember you do the same action on BOTH sides..
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #5

    Jun 13, 2012, 01:33 PM
    7x=3x-80
    7((times) how do u write times besides x)-3x+80=0
    (7-3)x+80=0
    4x+80=0
    now the q is hoe do I continue it?
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #6

    Jun 13, 2012, 01:40 PM
    So you are here


    Just take 80 from both sides and then you'll see what to do next..
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #7

    Jun 13, 2012, 01:42 PM
    hu I don't get that so u add 4x+80??
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #8

    Jun 13, 2012, 01:44 PM
    You want to move the 80 to the left in the form
    so you get



    What's next ?
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #9

    Jun 13, 2012, 01:49 PM
    So then u divide 80 divided by 4 and u get -20??
    If it correct thanks sooooo much :)
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #10

    Jun 13, 2012, 01:50 PM
    Do you see how that worked ?
    Same action on both sides..
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #11

    Jun 13, 2012, 01:50 PM
    Yes thxn so much!
    Can u also help me w/ another problom?
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #12

    Jun 13, 2012, 01:51 PM
    Lets see what we can do then..
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #13

    Jun 13, 2012, 01:56 PM
    kk the next one is
    5(2x-3)=6x=9
    I have so far is..
    5(2x-3)=6x=9
    10x-15-6x-9=0
    10x-24-6=0
    10x-6x-24=0
    4x-24=0
    4x=24
    x=6
    is that correct??
    if it is thanks soooooo much u rock I have a math final tom and u helped me a lot! :) <3
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #14

    Jun 13, 2012, 01:57 PM
    5(2x-3)=6x=9 this is incorrect as there's two = signs.
    what should the second one be ?
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #15

    Jun 13, 2012, 02:00 PM
    I don't know but how would u figure it out?
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #16

    Jun 13, 2012, 02:02 PM
    Well reread your work book ;)

    If it's + then your working is dead right..
    Does it make sense for you now ?

    What to try another..
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #17

    Jun 13, 2012, 02:04 PM
    Yes it is a + srry about that but thanks so much you ill ask you another one soon k thanks so much I apreaciate it :) <3
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #18

    Jun 13, 2012, 02:22 PM
    so here's another one...
    2(4c-7)=8c+14
    8c-14-8c+14
    8c-8c-14+14
    = 0
    so the answer is 0?
    is it right?
    Curlyben's Avatar
    Curlyben Posts: 18,514, Reputation: 1860
    BossMan
     
    #19

    Jun 13, 2012, 02:24 PM
    No need to post it here.
    Keep the problems in the same place ;)
    Makes it easier for my old brain to work on...
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #20

    Jun 13, 2012, 02:26 PM
    Kk lol
    Wait what do u mean "Keep the problems in the same place "?

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