[nfoland]

I-------I------------I
I... I... I
9V... 680ohm... 330ohms
I... I... I
I... I... 150ohms
I-------I------------I

The I's, dashes, and values represent a circuit. The periods are there to fill in the space. What is the voltage, current, and power of each resistor?

[nfoland]

It didn't make the image like I wanted it to. The 150 ohm and 330 ohm resistors are suppose to be in the same line with the 330 on top of the 150.

[ebaines]

I redrew the circuit to make it clearer. First start with the 680 ohm resistor. Since it's connected directly to the battery, the voltage across it is 9 volts. You can find current from Ohm's law (V=iR) and power from either or .

For the resistors on the right recall that two resistors in series are like one resistor of value R1 + R2. That single equivalent resistor is connected directly to 9 volts, so the current flow from Ohm's Law is

.

Now for power - there are two ways to do this:
a) since you now know the current flow through the two resistors, you can use and

b) or you could recognize that the voltage drops across resistor 1 and 2 are:



Then use :

and .

I suggest practicing both methods so you are comfortable with them.

[nfoland]

Thank you so much!