Ask Experts Questions for FREE Help !
Ask
    jamillamionette's Avatar
    jamillamionette Posts: 1, Reputation: 1
    New Member
     
    #1

    Jan 30, 2012, 11:37 AM
    Academically
    An antenna is on top of a TV transmission tower.at a point 236 m from the base of the tower, the angle of elevation of the top and end of the antenna are 42 degree 20 minutes and 44 degree 10 minutes respectively. Find the height of the tower and the height of the antenna.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
    Expert
     
    #2

    Jan 30, 2012, 01:36 PM
    Let's start with calculating the height of the anrenna. You have a right angle triangle formed by the ground, the antenna, and the line of sight to the top of the antenna. From trigonometry:

    tangent(42 deg 20 min) = (height of antenna)/236m

    So:

    height = 236 x tangent(42 deg 20min).

    If you know how to find the tangent of 42 degrees 20 minutes you will get your answer. Depending how your calculator is set up you will probably have to convert 42 deg 20 min into degrees only - recall that there are 60 minutes in one degree so 20 minutes = 1/3 degree.

Not your question? Ask your question View similar questions

 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.



View more questions Search