 |
|
| Browse | Ask | Answer | Search | Join/Login |
|
|
||||
|
Ramp With Friction
When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 2.41 m/s. The mass stops a distance S2 = 2.1 m along the level part of the slide. The distance S1 = 1.24 m and the angle θ = 33.70°. Calculate the coefficient of kinetic friction for the mass on the surface.
|
||||
Check out some similar questions!
Print ViewProblem 5.64 A 4.68 kg box sits at rest at the bottom of a ramp that is 8.36 m long and that is inclined at 40.0^\circ above the horizontal. The coefficient of kinetic friction is 0.40, and the coefficient of static friction is 0.50. Part A What constant force F , applied parallel to...
A frictionless track is to be built as shown, with L= 4.7 m and H= 4.6 m. In order to get the cart to slide from the top to the end of the track in the minimum time, how long should the distance D be? Assume that the speed of the cart on the horizontal surface is the same as at the bottom of the...
A frictionless track is to be built as shown, with L= 4.6 m and H= 3.9 m. In order to get the cart to slide from the top to the end of the track in the minimum time, how long should the distance D be? Assume that the speed of the cart on the horizontal surface is the same as at the bottom of the...
:confused: :confused: A force of 30.0 N is required to start a 4.4 kg box moving across a horizontal concrete floor. (a) What is the coefficient of static friction between the box and the floor? (b) If the 30.0 N force continues, the box accelerates at 0.50 m/s2. What is the coefficient of...
View more questions Search
| Question Tools | Search this Question |
Add your answer here.
|
