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Ms.Jones · Dec 18, 2011, 01:12 PM

how do I solve for x^2 3x -10

vannabannabear · Dec 18, 2011, 04:43 PM

Go to mathway.com ; They do math problems for free, in seconds.

corrigan · Dec 18, 2011, 06:09 PM

I'm assuming you mean $x^2 +3x -10$ . You can't solve it. You need an equals sign and something on the other side.

Aurora2000 · Dec 19, 2011, 02:37 AM

If you want the roots of $x^2+3x-10$ (values for which $x^2+3x-10 =0$ ) then use the formula for II degree polynomials:

the roots of $ax^2+bx+c$ are

$\frac{-b-\sqrt{b^2-4ac}}{2a},\qquad \frac{-b+\sqrt{b^2-4ac}}{2a}$

TUT317 · Dec 19, 2011, 04:44 PM

Originally Posted by vannabannabear

Go to mathway.com ; They do math problems for free, in seconds.

I would disagree with that advice. This website is very fortunate to have so many people who are not only good at mathematics but are also very good at explaining how problems are solved. There is no point in just getting the answer. You learn very little or nothing at all.

Tut