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    aksaa's Avatar
    aksaa Posts: 2, Reputation: 1
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    #1

    May 25, 2011, 07:33 AM
    Maths problems chapter 4 solved proportions?
    1440 men had sufficient food for 32 days. How many men may leave so that the same food be sufficient for 40 days when the ration is increased by 11/2 times?(hint:The 1st element is 1 and the 2nd is 3/2 in the ratio for ration.)
    aksaa's Avatar
    aksaa Posts: 2, Reputation: 1
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    #2

    May 25, 2011, 07:41 AM
    1440 men had sufficient food for 32 days. How many men may leave so that the same food be sufficient for 40 days when the ration is increased by 3/2 times?(hint:The 1st element is 1 and the 2nd is 3/2 in the ratio for ration.)
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #3

    May 25, 2011, 08:55 AM

    1440 men <=> 32 days

    40 days, with the same amount of food would obviously mean that there should be less men. So, as days increase, men decrease, meaning that men shares an inverse relationship with food.





    The k comes when you remove the proportionality sign. Solve for k using the values given in the first statement and then find men when you have food and k for the second part.
    zaki khalil's Avatar
    zaki khalil Posts: 1, Reputation: 1
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    #4

    Jul 22, 2011, 08:27 AM
    672
    uzair00777's Avatar
    uzair00777 Posts: 1, Reputation: 2
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    #5

    Nov 11, 2011, 10:24 PM
    Days :Ration :Men
    (down) 32 :(down arrow) 1 : 1440 (up arrow)
    40 : 3/2 : X

    X/1440 = 1/(3/2) * 32/40
    X = 2/3 * 32/40 * 1440
    X = 768
    Remaining men = 1440 - 768
    = 672 Men By Uzair hashmi 8th standard

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