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Uber Member
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Mar 13, 2011, 04:51 AM
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Right, now,
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Junior Member
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Mar 13, 2011, 04:54 AM
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1400(4a+b) / 196?
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Uber Member
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Mar 13, 2011, 04:56 AM
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Then, why did you tell me that:
?
If you did what you just did to 14 up there, you'd have:
:eek:
So, some confusion from your part? :confused:
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Junior Member
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Mar 13, 2011, 05:06 AM
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So it should be 1400(4a+b) / 14
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Uber Member
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Mar 13, 2011, 05:12 AM
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Yes, now you got it.
And what can you do now? Do you see why I chose to multiply both sides by 14? You can now reduce the fraction.
Just like you reduce 200/2 to 100/1 to finally 100.
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Junior Member
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Mar 13, 2011, 05:17 AM
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So its (4a+b) / 100?
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Uber Member
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Mar 13, 2011, 05:39 AM
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Try again...
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Junior Member
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Mar 13, 2011, 05:42 AM
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(100)(4a+b)?
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Uber Member
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Mar 13, 2011, 05:56 AM
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Right! :)
Now let's do another one, still to solve this problem.
Can you divide both sides by 100? :)
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Junior Member
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Mar 13, 2011, 05:59 AM
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126=(1)(4a+b)?
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Uber Member
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Mar 13, 2011, 06:10 AM
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Good! Now, save this for later. The other one now.
Can you try putting it in the form of the one you just did?
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Junior Member
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Mar 13, 2011, 06:12 AM
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can you show me the final step for 126 = (1)(4a+b)?
so that the other one I know how to do.
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Junior Member
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Mar 13, 2011, 06:14 AM
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the other part is 112 = (1)(6a+b)
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Uber Member
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Mar 13, 2011, 07:02 AM
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Originally Posted by henrypoo
the other part is 112 = (1)(6a+b)
Geesh, it's only now that I notice that you made a wrong calculation earlier, 9000*14 = 126,000, not 12,600.
Not quite. I get:
1120 = 6a + b
(after distributing 1 into the brackets)
Okay, now we have:
1260 = 4a + b
1120 = 6a + b
We can get a and b from there. Subtract both equations:
Code:
1260 = 4a + 1b
1120 = 6a + 1b -
= a + b
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Junior Member
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Mar 13, 2011, 07:04 AM
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sorry sorry. To sum up the other question. I have done the 2 equation.
0= 4a+b -126
0= 6a+b - 112
from the above I can find a and b using stimultaneuos equation?
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Uber Member
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Mar 13, 2011, 07:12 AM
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Right, a correction is to be made through, it's 1260 and 1120 and one last thing, you posted in the wrong thread :p
Ok, I'm moving those posts.
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