Um... I think that you have got some concepts wrong...
First of all, in your equation, you are already told that the oxygen is
and not
'the oxygen present in the air' this only means the oxygen that you have in the air, the oxygen that you breathe.
In your equation, it is written 4Al. This means that 4 moles of Al will react. This doesn't mean that
will react... this doesn't even 'exist'. So, we get:
b)how many unit of Aluminum oxide was Created in the process?
Um... I'm not sure what does 'unit' refer to exactly... It seems really strange since in the previous part, you already found the number of moles of Al2O3 and from this calculated the mass of Al2O3 produced...
c)What is material reacts and What amount in gr are left from the same material in the end of the Process
hope now is more Clear.
This is still not so clear...
From your calculations, you should see that oxygen reacts completely and aluminium remains/is left behind.
You only need to work out the number of moles of Al used, and subtract this from the initial number of moles of Al, then find the mass.