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DOAalex · Mar 30, 2010, 08:57 PM

How do you solve 6x-6y-4z=-10, -5x+4y-z=-12, 2x+3y-2z=9 3 variables using elimination
I really need help so please help me! Thanks

InfoJunkie4Life · Mar 31, 2010, 10:23 AM

$6x - 6y - 4z = -10$

$-5x + 4y - z = -12$

$2x + 3y - 2z = 9$

Elimination = Addition

Sometimes you have to modify the equation (Remember what you do to one side you must also do to the other)

$-2(2x + 3y - 2z = 9)$

$-4x - 6y + 4z = -18$

$6x - 6y - 4z = -10$
+ $-4x - 6y + 4z = -18$
-----------------------------------
$2x - 12y + 0z = -28$