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    CATSDOGS's Avatar
    CATSDOGS Posts: 1, Reputation: 1
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    #1

    Feb 11, 2010, 02:45 PM
    graph 2csc(2x)
    I need help on trigonometric functions! I don't understand, I'm getting mad, I have no clue what to do or where 2 start. i need help!!!
    bulksalty's Avatar
    bulksalty Posts: 31, Reputation: 3
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    #2

    Feb 11, 2010, 02:51 PM

    normally graphs are made by entering a few points until you can see a curve forming.

    So you'd pick some values for x (good choices are -2, -1, 0, 1, 2) and find out what y would equal (in your example that means plugging in each of these values into your equation so for the first it's 2*-2 then find the cosecant of that, then multiply that by 2 and plot the point. Repeat for the other 5 points.

    However, what you'll find is that as you expand outward there will be points where the function becomes undefined, and after those points the y values will flip. Cosecant and secant functions look like big letter U s alternating between Us that are right side up and Us that are up side down.
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #3

    Feb 11, 2010, 04:20 PM

    You don't have a graphing calculator? Remember, csc(2x)=1/sin(2x).

    sin(2x)=0 when , therefore, that is why the graph heads toward infinity when x is a multiple of Pi/2. Let C=... -3,-2,-1,0,1,2,3,.
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