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    hslove142331's Avatar
    hslove142331 Posts: 71, Reputation: 1
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    #1

    Feb 6, 2010, 08:09 PM
    How can I find the molality of sucrose in mixture?
    To make a particular sweet substance, A concentrated sucrose solution is boiled until the temperature reaches 267ºF.

    I don't know how can I find molality , they give me only temperature.
    How can I molality, I think I need to find moles of solute and kg of solvent.
    Please help
    tileguy's Avatar
    tileguy Posts: 11, Reputation: 2
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    #2

    Feb 8, 2010, 06:21 PM

    increase in Temp (must convert to C) = I(1 for sugar) x K X molality. K for water (boiling) is 0.51 C .

    This gives you the amount over 100C = .51C x molality. Solve for molality. This is called a colligative property of a solution.
    hslove142331's Avatar
    hslove142331 Posts: 71, Reputation: 1
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    #3

    Feb 8, 2010, 09:17 PM
    So, its going to be 196?
    tileguy's Avatar
    tileguy Posts: 11, Reputation: 2
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    #4

    Feb 8, 2010, 10:18 PM
    Quote Originally Posted by hslove142331 View Post
    so, its gonna be 196??
    196 What?
    1) You must convert to C
    2) Your temp is 130.6 C or 30.6 C above the normal boiling point
    3) Your equation now is 30.6 C = (I)(K)(m)
    4) Plug in your numbers 30.6 C = (1)(.51 C) (m)
    5) Your molality is 60 or 60 moles per kilogram of water - a silly number - 20 kilos of sugar in 1 kilo of water. That is quite a syrup.

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