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    nikki2424's Avatar
    nikki2424 Posts: 2, Reputation: 1
    New Member
     
    #1

    Dec 15, 2009, 01:46 PM
    how would you solve for n if 9n-10=71
    9n-10=71
    9n+10=+10
    9n=81
    9n/9=81/9
    n=9
    nikki2424's Avatar
    nikki2424 Posts: 2, Reputation: 1
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    #2

    Dec 15, 2009, 02:01 PM

    This is correct
    mathwiz3502's Avatar
    mathwiz3502 Posts: 121, Reputation: 1
    Junior Member
     
    #3

    Dec 15, 2009, 03:13 PM
    It is exactly correct
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #4

    Dec 16, 2009, 07:32 AM

    Although you got the answer, I don't suggest you put it as you put it. Because the way you put it is confusing.

    Quote Originally Posted by nikki2424
    ]9n-10=71
    9n+10=+10
    9n=81
    9n/9=81/9
    n=9
    Where does the bold part come from?

    You have to show this:

    9n - 10 +10 = 71 + 10

    and not directly add 10, because the other side is not only '10'.
    Ajama4's Avatar
    Ajama4 Posts: 2, Reputation: 1
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    #5

    Dec 20, 2009, 07:01 PM

    You are correct
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #6

    Dec 20, 2009, 07:22 PM

    The check is:

    9(9)-10 = 71; which is true, so you got the right answer.

    I'm in agreement that it was confusing getting there.

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