(N+3)(2n+3)=(n+2)2+(n-2)2

tseligman · Dec 1, 2009, 07:09 PM

How do you solve the "N" in the following equation when the right side is squared (N+3)(2n+3)=(n+2)2+(n-2)2

InfoJunkie4Life · Dec 2, 2009, 01:02 AM

If your equation is:
$(n + 3)(2n + 3) = (n + 2)^2 + (n - 2)^2$
then
$2n^2 + 9n + 9 = n^2 + 4n + 2 + n^2 + 4$
Foiled
$2n^2 + 9n + 9 = 2n^2 + 4n + 6$
Simplified

Next, move all "n" terms to one side and all number terms to the other.
$2n^2 - 2n^2 +9n - 4n = 6 - 9$

$5n = -3$
simplified
$n = \frac{-3}{5}$
answer

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